If so, good for you. Temulin despises sciences that are really math with another face.
Would Pb2+ + 2Br- → PbBr2
Still be considered a redox reaction even though both reactants/products end up with the same final charge?
Any Good at Chem?
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USSRGirl - Posts: 1266
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This isn't a redox reaction; however, I must warn you that all charges are always conserved, whether or not any of the species are being oxidized or reduced.
Job 7:16
I loathe my life; I would not live forever. Let me alone, for my days are but a breath.
I loathe my life; I would not live forever. Let me alone, for my days are but a breath.
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Ingemar - Posts: 2244
- Joined: Sun Mar 28, 2004 12:43 pm
- Location: A Dungeon
Yes I am alive, and the Tournaments have been replaced with the Free-For-Alls, which allow more freedom since there are no predetermined brackets.
If you hate math-Chemistry so much, why not look into Organic Chemistry? (Though unfortunately OChem isn't understandable on a meaningful level without knowledge of Schroedinger's wavefunctions, which involves a lot of hairy equations with EEEEEVIL greek letters).
If you hate math-Chemistry so much, why not look into Organic Chemistry? (Though unfortunately OChem isn't understandable on a meaningful level without knowledge of Schroedinger's wavefunctions, which involves a lot of hairy equations with EEEEEVIL greek letters).
Job 7:16
I loathe my life; I would not live forever. Let me alone, for my days are but a breath.
I loathe my life; I would not live forever. Let me alone, for my days are but a breath.
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Ingemar - Posts: 2244
- Joined: Sun Mar 28, 2004 12:43 pm
- Location: A Dungeon
*bangs head on desk* Anyone know how to this demonic problem?
A gas sample occupies a volume of 8 L at 20°C. The temperature at which the gas would double its volume while keeping the pressure the same is ________.
I thought the P always changed with V. T__T;; I have 586 K as my answer currently, but I'm wondering if it wouldn't be 273 K.
A gas sample occupies a volume of 8 L at 20°C. The temperature at which the gas would double its volume while keeping the pressure the same is ________.
I thought the P always changed with V. T__T;; I have 586 K as my answer currently, but I'm wondering if it wouldn't be 273 K.
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USSRGirl - Posts: 1266
- Joined: Sun Feb 12, 2006 11:14 am
- Location: In The Place Where There Is No Darkness...
P does change with V.....and don't forget that you have to convert Celcius to Kelvins.....
273K is basically 0Celcius......
So it looks as if your original answer is correct...
( Man! It's been forever since I did this kinda stuff! @,@)
273K is basically 0Celcius......
So it looks as if your original answer is correct...
( Man! It's been forever since I did this kinda stuff! @,@)
Jeremiah 29:11-"For I know the plans I have for you," declares the Lord,"plans to prosper you and not to harm you, plans to give you hope and a future."
"All the world's a stage and all the men and women merely players; they have their entrances and their exits and one man in his time plays many parts."-Will Shakespeare
@)}~ carry this rose in your sig, as thanks, to all the CAA Moderators
"All the world's a stage and all the men and women merely players; they have their entrances and their exits and one man in his time plays many parts."-Will Shakespeare
@)}~ carry this rose in your sig, as thanks, to all the CAA Moderators
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Phantom_Sorano - Posts: 909
- Joined: Sat Mar 11, 2006 5:19 pm
- Location: Between the past and the future.
A gas sample occupies a volume of 8 L at 20°C. The temperature at which the gas would double its volume while keeping the pressure the same is ________.
Okay. You're told the pressure is constant. You are given a volume 8 L, so V1= 8 L. It tells you your second volume will be twice that, thus V2 = 16 L. T1 is 20 C + 273 = 293 K. You are solving for T2. Since PV = nRT, V and T are directly proportional, so if one goes up, so must the other.
V1/T1=V2/T2 which is Charle's Law.
This can be represented by shrinking a balloon in liquid nitrogen. The cold makes the volume contract sharply.
I'm a second year Ph D in chemistry by the way. I teach freshmen chem.
Okay. You're told the pressure is constant. You are given a volume 8 L, so V1= 8 L. It tells you your second volume will be twice that, thus V2 = 16 L. T1 is 20 C + 273 = 293 K. You are solving for T2. Since PV = nRT, V and T are directly proportional, so if one goes up, so must the other.
V1/T1=V2/T2 which is Charle's Law.
This can be represented by shrinking a balloon in liquid nitrogen. The cold makes the volume contract sharply.
I'm a second year Ph D in chemistry by the way. I teach freshmen chem.
[color="Red"]As a man thinks in his heart, so is he. - Proverbs 23:7[/color]
The Sundries
Robin: "If we close our eyes, we can't see anything."
Batman: "A sound observation, Robin."
The Sundries
Robin: "If we close our eyes, we can't see anything."
Batman: "A sound observation, Robin."
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Doubleshadow - Posts: 2102
- Joined: Sat Nov 13, 2004 7:04 pm
- Location: ... What's burning?
Help.
The following chemical reaction has reached equilibrium:
2NO + O2 <-> 2NO2
Calculate the equilibrium constant (Keq) if the concentrations of reactants and products are 1.26 × 10-10 M for NO, 2.28 × 10-3 M for O2, and 9.32 × 10-6 M for NO2.
a. 3.28 × 10^-7
b. 2.40 × 10^-12
c. 2.40 × 10^12
d. 2.61 × 10^-17
I vote a. o.O
In the following equation 2 Y (g) + X (g) → C (g) at 100°C the following data were obtained:
Initial concentration Y:
0.010
0.020
0.030
0.030
Initial concentration X:
0.010
0.010
0.010
0.020
Rate:
1.2 x 10^-3
2.4 x 10^-3
3.6 x 10^-3
14.4 x 10^-3
The rate of law for this reaction is __________.
a. k[Y][X]
b. k[Y]2[X]2
c. k[Y][X]2
d. k[Y]2[X]
... I have no clue. C?
The following chemical reaction has reached equilibrium:
2NO + O2 <-> 2NO2
Calculate the equilibrium constant (Keq) if the concentrations of reactants and products are 1.26 × 10-10 M for NO, 2.28 × 10-3 M for O2, and 9.32 × 10-6 M for NO2.
a. 3.28 × 10^-7
b. 2.40 × 10^-12
c. 2.40 × 10^12
d. 2.61 × 10^-17
I vote a. o.O
In the following equation 2 Y (g) + X (g) → C (g) at 100°C the following data were obtained:
Initial concentration Y:
0.010
0.020
0.030
0.030
Initial concentration X:
0.010
0.010
0.010
0.020
Rate:
1.2 x 10^-3
2.4 x 10^-3
3.6 x 10^-3
14.4 x 10^-3
The rate of law for this reaction is __________.
a. k[Y][X]
b. k[Y]2[X]2
c. k[Y][X]2
d. k[Y]2[X]
... I have no clue. C?
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USSRGirl - Posts: 1266
- Joined: Sun Feb 12, 2006 11:14 am
- Location: In The Place Where There Is No Darkness...
Alright. The first problem is already in equilibrium so all you have to do is set up the equilibrium expression and plug in the molarities. The equilibrium expression is products over reactants where the molecules with a 2 as the coefficient are squared (the NO and NO2). So, square NO2, the divide it by O2 and NO squared.
Rate laws are set up by seeing how change in molarity effect the reaction. For Y, every time you increase the concentration, the rate increases proportionally. Double the concentration it goes twice as fast, triple it it goes three times as fast, so the Y is raised to the 1. For X when you doubled the concentration, the rate got 4 times as fast, so X is proportional to the square, meaning the exponent for X is a 2.
Rate laws are set up by seeing how change in molarity effect the reaction. For Y, every time you increase the concentration, the rate increases proportionally. Double the concentration it goes twice as fast, triple it it goes three times as fast, so the Y is raised to the 1. For X when you doubled the concentration, the rate got 4 times as fast, so X is proportional to the square, meaning the exponent for X is a 2.
[color="Red"]As a man thinks in his heart, so is he. - Proverbs 23:7[/color]
The Sundries
Robin: "If we close our eyes, we can't see anything."
Batman: "A sound observation, Robin."
The Sundries
Robin: "If we close our eyes, we can't see anything."
Batman: "A sound observation, Robin."
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Doubleshadow - Posts: 2102
- Joined: Sat Nov 13, 2004 7:04 pm
- Location: ... What's burning?
So, it's a calculator issue? Anyway, to whenever you raise a power to a power you multiply them, so a (10^-7)^2 is 10^-14.
[color="Red"]As a man thinks in his heart, so is he. - Proverbs 23:7[/color]
The Sundries
Robin: "If we close our eyes, we can't see anything."
Batman: "A sound observation, Robin."
The Sundries
Robin: "If we close our eyes, we can't see anything."
Batman: "A sound observation, Robin."
-
Doubleshadow - Posts: 2102
- Joined: Sat Nov 13, 2004 7:04 pm
- Location: ... What's burning?
Well, first I wasn't sure if you still raised them to the coefficient. But I still don't seem to be getting the right answer here.
I did 9.32 x 10^-12/1.26 × 10^-20 x 2.28 x 10^-6 and got 3.24^17 according to my calculator.
I did 9.32 x 10^-12/1.26 × 10^-20 x 2.28 x 10^-6 and got 3.24^17 according to my calculator.
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USSRGirl - Posts: 1266
- Joined: Sun Feb 12, 2006 11:14 am
- Location: In The Place Where There Is No Darkness...
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