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Algebra II - Factoring and Imaginary Numbers

PostPosted: Wed Dec 07, 2005 2:36 pm
by Destroyer2000
This is the first time I've ever asked for help here, but this stuff is annoying. And I have a test tomorrow. I'm going to use / for a fraction line, alright?

If I have 4 times the square root of 3 multiplied by the square root of 21, what do I do? I know that..say, the square root of six times the square root of 15 is the square root of 90, and I have to simplify it down from there. I HAVE to make a 100 on that test tomorrow to pull my grade up high enough to offset the bad one I made last 9 weeks. I have a 95 or so now. If I make a 100 here, I should have a 97, which will pull up my 82 to a 90 for the semester.

PostPosted: Wed Dec 07, 2005 2:57 pm
by Technomancer
You have 4*sqrt(3)*sqrt(21), which is 4*sqrt(3)*sqrt(3*7). Remembering the properties of the sqrt operator, this gives us 4*sqrt(3*3*7), which is 4*3*sqrt(7). The simplified expression is thus 12*sqrt(7).